tan^2x=(1/cos^2x)-1 - solution

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Solution for tan^2x=(1/cos^2x)-1 equation:

-((3/8)*n)-1 = -1

(y-1)^2*sin(3.14*x)

4/x = x/4

y/4 > -13

((2^4*x^8*y^4)/(2*x^8))*y^4 = 0

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